x^2+17x-41.25=0

Solution for x^2+17x-41.25=0 equation:

x^2+17x-41.25=0

a = 1; b = 17; c = -41.25;
Δ = b2-4ac
Δ = 172-4·1·(-41.25)
Δ = 454
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{454}}{2*1}=\frac{-17-\sqrt{454}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{454}}{2*1}=\frac{-17+\sqrt{454}}{2}
$